b^2+4b=32

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Solution for b^2+4b=32 equation:


Simplifying
b2 + 4b = 32

Reorder the terms:
4b + b2 = 32

Solving
4b + b2 = 32

Solving for variable 'b'.

Reorder the terms:
-32 + 4b + b2 = 32 + -32

Combine like terms: 32 + -32 = 0
-32 + 4b + b2 = 0

Factor a trinomial.
(-8 + -1b)(4 + -1b) = 0

Subproblem 1

Set the factor '(-8 + -1b)' equal to zero and attempt to solve: Simplifying -8 + -1b = 0 Solving -8 + -1b = 0 Move all terms containing b to the left, all other terms to the right. Add '8' to each side of the equation. -8 + 8 + -1b = 0 + 8 Combine like terms: -8 + 8 = 0 0 + -1b = 0 + 8 -1b = 0 + 8 Combine like terms: 0 + 8 = 8 -1b = 8 Divide each side by '-1'. b = -8 Simplifying b = -8

Subproblem 2

Set the factor '(4 + -1b)' equal to zero and attempt to solve: Simplifying 4 + -1b = 0 Solving 4 + -1b = 0 Move all terms containing b to the left, all other terms to the right. Add '-4' to each side of the equation. 4 + -4 + -1b = 0 + -4 Combine like terms: 4 + -4 = 0 0 + -1b = 0 + -4 -1b = 0 + -4 Combine like terms: 0 + -4 = -4 -1b = -4 Divide each side by '-1'. b = 4 Simplifying b = 4

Solution

b = {-8, 4}

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